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s = ½gt²

PHY006 · Mechanics · Classes 9–11

Free fall

Objective: To study the motion of a freely falling object and find how distance depends on time.

🧰 Apparatus

  • Steel ball
  • Electromagnet release
  • Light gates or video camera with a scale
  • Metre scale

📐 Formulas and SI units

s = ½gt² (m)
v = gt (m/s)
t = √(2h/g) (s)

💡 Theory

In free fall every object near the Earth accelerates at g ≈ 9.8 m/s², whatever its mass (ignoring air resistance). Distance grows with the square of time: s = ½gt², so in equal time intervals the distances fallen are in the ratio 1 : 3 : 5 : 7.

🪜 Procedure

  1. Release the ball from rest beside a vertical scale.
  2. Record the fall with a video at a known frame rate (or use light gates).
  3. Read the position at equal time intervals.
  4. Plot s against t² and find the slope (= g/2).
  5. Repeat with a different ball mass.

📋 Observations Simulated values

✅ Result and conclusion

A 20 m drop takes 2.02 s and lands at 19.8 m/s; heavy and light balls fall together.

🔬 In a real lab

Air resistance slows light or large objects (a feather falls slowly); in a vacuum tube all objects fall together.

⚠️ Safety

Drop only small balls into a sand tray; never drop objects from height where people walk.

❓ Quick check

1. A heavy and a light ball dropped together (no air)…

2. Distance fallen in the first second?

3. Speed after 3 s of free fall?

🏋️ Practice

EasyTime to fall 45 m?

Answer: ≈ 3.03 s

MediumDistances in successive seconds are in the ratio…?

Answer: 1 : 3 : 5 : 7

ChallengeA stone falls for 2 s. Distance?

Answer: 19.6 m