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τ = Iα

PHY009 · Mechanics · Classes 11–12 + College

Moment of inertia

Objective: To compare the moments of inertia of different shapes and see how they resist angular acceleration.

🧰 Apparatus

  • Disc, ring and sphere of equal mass and radius
  • Axle with a string and falling mass
  • Stopwatch
  • Metre scale

📐 Formulas and SI units

τ = Iα
I: disc ½MR², ring MR², solid sphere ⅖MR², rod (centre) ML²/12

💡 Theory

Moment of inertia I measures how hard it is to change rotation. It depends on how far the mass is from the axis: a ring (I = MR²) is harder to spin than a disc (½MR²). Newton's second law for rotation is τ = Iα.

🪜 Procedure

  1. Mount the disc on the axle and wind the string.
  2. Let the falling mass apply a steady torque.
  3. Time how long the disc takes to reach a set speed, or measure α.
  4. Repeat with the ring and the sphere.
  5. Calculate I = τ/α and compare with the formulas.

📋 Observations Simulated values

✅ Result and conclusion

A 2 kg disc of radius 0.5 m has I = 0.25 kg m², so a 2 N m torque gives α = 8 rad/s²; the ring accelerates half as fast.

🔬 In a real lab

Axle friction and the string's inertia add errors; real discs have a hub and holes that change I.

⚠️ Safety

Keep fingers, hair and loose clothes away from spinning objects.

❓ Quick check

1. Which spins up fastest with the same torque (same M and R)?

2. Unit of moment of inertia?

3. Moving mass away from the axis makes I…

🏋️ Practice

EasyRing, 1 kg, 0.2 m. I?

Answer: 0.04 kg m²

MediumI = 0.5 kg m², τ = 2 N m. α?

Answer: 4 rad/s²

ChallengeWhy do skaters pull their arms in to spin faster?

Answer: I decreases, so ω increases (angular momentum conserved)