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V_out ≈ V_z

PHY066 · Electronics · Class 12 + College

Zener voltage regulation

Objective: To show that a Zener diode keeps the output voltage nearly constant when the input voltage changes.

🧰 Apparatus

  • Zener diode (5.1 V)
  • Series resistor (330 Ω)
  • Load resistor (1 kΩ)
  • Variable DC supply (0–20 V)
  • Two voltmeters, milliammeter

📐 Formulas and SI units

I = (V_in − V_z) / R
I_Z = I − I_L; I_L = V_z / R_L

💡 Theory

A Zener diode is used in reverse bias. Once the reverse voltage reaches V_z it conducts just enough to hold its voltage at V_z, absorbing the extra current. The series resistor drops the rest: I = (V_in − V_z)/R. So the load sees a steady V_z.

🪜 Procedure

  1. Connect the series resistor, Zener (reverse) and load as shown.
  2. Increase V_in from 0 in steps.
  3. Record V_in, V_out and the currents.
  4. Plot V_out against V_in and find where it levels off.
  5. Change the load and check V_out stays steady.

📋 Observations Simulated values

✅ Result and conclusion

With 12 V in, 330 Ω and a 5.1 V Zener, 20.9 mA flows through R; the output stays at 5.1 V for any input above about 6.8 V.

🔬 In a real lab

The Zener voltage rises slightly with current and temperature; real output changes by a few tens of millivolts.

⚠️ Safety

Low-voltage DC only; check the Zener's power rating (I_Z × V_z) so it does not overheat.

❓ Quick check

1. A Zener regulator uses the diode in…

2. If V_in rises, the Zener current…

3. Purpose of the series resistor?

🏋️ Practice

EasyV_in = 9 V, V_z = 5 V, R = 200 Ω. I?

Answer: 20 mA

MediumPower in a 5.1 V Zener carrying 15 mA?

Answer: ≈ 77 mW

ChallengeName a use of a Zener regulator.

Answer: Steady supply for small circuits, reference voltages